If $a$ and $b$ are the position vectors of $A$ and $B$ respectively,then the position vector of a point $C$ on $AB$ produced such that $\overrightarrow{AC} = 3\overrightarrow{AB}$ is

  • A
    $3a - b$
  • B
    $3b - a$
  • C
    $3a - 2b$
  • D
    $3b - 2a$

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